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(1)(y^3)^2+(y^2)^3-2y*y^5 (2)(3x+2)(3x-2)-5x(x-1)-(2x-1)(2x-1)
人气:328 ℃ 时间:2020-03-17 10:37:46
解答
(1)(y^3)^2+(y^2)^3-2y*y^5
=y^6+y^6-2y^6
=0
(2)(3x+2)(3x-2)-5x(x-1)-(2x-1)(2x-1)
=9x²-4-5x²+5x-(4x²-4x+1)
=4x-5
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