令 g(x) = ln(1+x), g(0) = 0；[ln(1+x)] ' = 1 / (1+x),g'(0) = 1；[ln(1+x)] '' = -1 / (1+x)^2, g''(0) = -1；[ln(1+x)] ''' = 2 / (1+x)^3, g''(0) = 2!；一般有：[ln(1+x)] ^(k) =...