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4x^2+4x+y^2-2y+2=0,则x^3y-y^3x得值是?
若x^2(x-3)+3x-9能被x-a整除,则a的值是多少?
人气:193 ℃ 时间:2020-06-19 20:49:56
解答
4x^2+4x+y^2-2y+2= (4x^2+4x+1)+(y^2-2y+1)=(2x+1)^2+(y-1)^2=0
2x+1=0,y-1=0,x=-1/2,y=1
x^3y-y^3x=xy(x+y)(x-y)=-1/2*1/2(-3/2)=3/8
x^2(x-3)+3x-9=x^2(x-3)+3(x-3)=(x-3)(x^2+3) a=3
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