证明：∵Rt△ABC中,c为斜边长,a,b为直角边∴ c²=a²+b²从而 log2[1+(b +c)/a]+log2[1+(a-c)/b]=log2[(a+b+c)/a]+log2[(b+a-c)/b]=log2[(a+b+c)(b+a-c)/(ab)]=log2[(a+b)²-c²)/(ab)]=log2[(a...