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分解因式 x-y-x²+2xy-y²+2
人气:484 ℃ 时间:2020-06-30 09:39:43
解答
x-y-x²+2xy-y²+2
=-(x²-2xy+y²)+(x-y)+2
=-(x-y)²+(x-y)+2
=-[(x-y)²-(x-y)-2]
=-(x-y-2)(x-y+1)
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