sin2a+sina/cos2a+cosa+1=
人气：375 ℃ 时间：2020-01-27 21:08:18
解答
sin2a+sina/cos2a+cosa+1
=(2sinacosa+sina)/(2cos²a+cosa)
=sina(2cosa+1)/[cosa(2cosa+1)]
=sina/cosa
=tana
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