> 数学 >
数列{an}中,若a1=1,an+an+1
1
2n
(n∈N*),则
lim
n→∞
(a1+a2+…+a2n)
=______.
人气:483 ℃ 时间:2020-06-11 12:05:46
解答
an+an+1
1
2n
,得(a1+a2)+(a3+a4)+…+(a2n-1+a2n)=
1
2
+
1
23
+…+
1
22n−1

=
1
2
(1−
1
4n
)
1−
1
4
=
2
3
(1−
1
4n
)

lim
n→∞
(a1+a2+…+a2n)
=
lim
n→∞
[
2
3
(1−
1
4n
)]
=
2
3

故答案为:
2
3
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