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计算1/2!+2/3!+3/4!+...+n/(n+1)!
人气:320 ℃ 时间:2020-05-22 01:04:53
解答
n/(n+1)!=[(n+1)-1]/(n+1)!=1/n!-1/(n+1)!
故1/2!+2/3!+3/4!+...+n/(n+1)!
=1-1/2!+1/2!-1/3!+1/3!-1/4!+.+1/n!-1/(n+1)!=1-1/(n+1)!
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