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解方程:2sin²(x/2)+5sin(x/2)-3=0
人气:186 ℃ 时间:2020-10-02 02:56:50
解答
2sin²(x/2)+5sin(x/2)-3=0
[2sin(x/2)-1][sin(x/2)+3]=0
sin(x/2)=-3舍去
所以sin(x/2)=1/2
x/2=2kπ+π/6,x/2=2kπ+5π/6
x=4kπ+π/3,x=4kπ+5π/3
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