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分解因式:x2-xy-2y2-x-y=______.
人气:307 ℃ 时间:2020-01-29 20:52:46
解答
x2-xy-2y2-x-y,
=(x2-xy-2y2)-(x+y),
=(x-2y)(x+y)-(x+y),
=(x+y)(x-2y-1).
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