cos(π+α)=-1/3,sin(3π/2-α)=
sin(π/3+α)=1/3,cos(5π/6+α)=
sin(α-π/4)=1/3,cos(π/4+α)=
人气:472 ℃ 时间:2020-06-02 17:57:53
解答
cos(π+α)=-1/3,sin(3π/2-α)=-1/3
sin(π/3+α)=1/3,cos(5π/6+α)=-1/3
sin(α-π/4)=1/3,cos(π/4+α)=-1/3有过程吗,我不明白直接得到
采纳吧第二第三个不懂
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