cos(π+α)=-1/3,sin(3π/2-α)=sin(π/3+α)=1/3,cos(5π/6+α)=sin(α-π/4)=1_数学解答

cos(π+α)=-1/3,sin(3π/2-α)=
sin(π/3+α)=1/3,cos(5π/6+α)=
sin(α-π/4)=1/3,cos(π/4+α)=

人气：309 ℃　时间：2020-06-02 17:57:53

解答

cos(π+α)=-1/3,sin(3π/2-α)=-1/3
sin(π/3+α)=1/3,cos(5π/6+α)=-1/3
sin(α-π/4)=1/3,cos(π/4+α)=-1/3有过程吗，我不明白直接得到
采纳吧第二第三个不懂