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三角函数最大值和最小值,
Find the maximum and minimum values of the function.(Round your answer to two decimal places.)
(cos x)/(5+sinx)
人气:289 ℃ 时间:2020-05-09 21:36:40
解答
y=cosx/(5+sinx)y'=[-sinx(5+sinx)-cosx cosx]/(5+sinx)^2=-(5sinx+1)/(5+sinx)^2=0---> sinx=-1/5所以有:最大值当sinx=-1/5,cosx=2√6/5,ymax=2√6/(25-1)=√6/12=0.20最小值当sinx=-1/5,cosx=-2√6/5,ymax=-2√6/...
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