> 数学 >
(1/2)gt^2-(1/2)g(t-1)^2=(7/16)*(1/2)gt^2这个方程怎么解的,
人气:262 ℃ 时间:2020-04-24 07:59:24
解答
(1/2)gt^2-(1/2)g(t-1)^2=(7/16)*(1/2)gt^2
t^2-(t-1)^2=(7/16)t^2
(9/16)t^2-(t-1)^2=0
(3t/4)^2-(t-1)^2=0
(3t/4-t+1)(3t/4+t-1)=0
t1=4t2=4/7
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版