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"(x+1)^2-4(x+1)+4" x-1=3的算木平方根
人气:216 ℃ 时间:2020-05-11 18:00:15
解答
x^2y^2(x-4y)(x+4y)-x^2y^2(x-2y)^2 =x^2y^2(x^2-16y^2-x^2+4xy-4y^2)
=x^2y^2(4xy-20y^2)
=4x^2y^3(x-5y)
当x=-2,y=1/2时,原式=4×(-2)^2×(1/2)^3×(-2-5×1/2)=-9
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