一道化简求值的数学题
化简求值:
若a=3 b=7 c=-2,求:a²-b²-c²+2ab/c²-a²-b²+2ab的值.
若回答正确,
人气:108 ℃ 时间:2020-04-15 20:33:11
解答
我准备用完全平方式和平方差公式算的,但题有点不对劲,我改了一下.
(a^2-b^2-c^2+2bc)/(c^2-a^2-b^2+2ab)
=[a^2-(b^2-2bc+c^2)]/[c^2-(a^2-2ab+b^2)]
=[a^2-(b-c)^2]/[c^2-(a-b)^2]
=[(a+b-c)(a-b+c)]/[(c+a-b)(c-a+b)]
=(a+b-c)/[-(a-b-c)]
代入为:
=[3+7-(-2)]/{-[3-7-(-2)]}
=12/2
=6
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