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数学
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1/a-b+1/a+b+2a/a²+b²+4a³/a的4次+b的4次=
人气:200 ℃ 时间:2020-03-21 00:42:09
解答
原式=(a+b+a-b)/(a²-b²)+2a/(a²+b²)+4a³/(a的4次方+b的4次方)=2a/(a²-b²)+2a/(a²+b²)+4a³/(a的4次方+b的4次方)=4a³/(a的4次方-b的4次方)+4a³/(...
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