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sin29π/6+cos(-29π/3)+tan(-25/4)
人气:377 ℃ 时间:2020-04-19 02:48:59
解答
sin29π/6+cos(-29π/3)+tan(-25π/4) =sin(24π/6+5π/6)+cos(-30π/3+π/3)+tan(-24π/4-π/4) =sin5π/6+cosπ/3-tanπ/4
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