> 数学 >
把下列各式因式分解.(1)x^3+3x^2+3x+9;(2)2x^2+xy-y^2-4x+5y-6
人气:327 ℃ 时间:2019-10-23 11:17:24
解答
(1)x^3+3x^2+3x+9
=x^2(x+3)+3(x+3)
=(x^2+3)(x+3)
(2)2x^2+xy-y^2-4x+5y-6
=(2x-y)(x+y)-4x+5y-6
=(2x-y)(x+y)+(2x+2y)-6x+3y-6
=(2x-y)(x+y)+2(x+y)-6x+3y-6
=(x+y)(2x-y+2)-3(2x-y+2)
=(2x-y+2)(x+y-3)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版