多项式x²-(m+1)x+m能被x+1整除,求m的值
人气:278 ℃ 时间:2020-04-14 20:24:26
解答
如果多项式中有因式X+1,则当X=-1时,X+1=0
此时该多项式的值一定为0
因此代入X=-1到X²-(m+1)X+m
1+(M+1)+M=0
2M+2=0
M=-1
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