解
y=sin³(3x+π/4)
y'=[sin³(3x+π/4)]'
=3sin²(3x+π/4)cos(3x+π/4)(3x+π/4)'
=9sin²(3x+π/4)cos(3x+π/4)y'=[sin³(3x+π/4)]'=3sin²(3x+π/4)[sin(3x+π/4)]'(3x+π/4)'=3sin²(3x+π/4)cos(3x+π/4)×3