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解方程组:(x+2)²-1=(x+3)(x-3)-4y (x-1)(y+6)=(x+2)(y+4)
人气:243 ℃ 时间:2020-06-12 04:47:27
解答
(x+2)²-1=(x+3)(x-3)-4y
(x-1)(y+6)=(x+2)(y+4)
4X+3=-9--4y
X=-3-y代入
(-3-y-1)(y+6)=(-3-y+2)(y+4)
(y+4)(y+6)=(y+4)(y+1)
y=-4
X=1
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