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1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y)]÷4y 3)
整式乘除 3)(a+b)^2-2a(b+1)-a^2b÷ab 4)(a^2+3)(a-3)-a(a^2-2a-2)
人气:338 ℃ 时间:2020-02-03 17:07:49
解答
1) (2x+5y)(2x-5y)(-4x^2-25y^2)=-(4x^2-25y^2)(4x^2+25y^2)=-(16x^4-625y^4)=625y^4-16x^42) [(x+y)(x-y)-(x-y)^2+2y(x-y)]÷4y=(x-y)(x+y-x+y+2y)÷4y=4y(x-y)÷4y^=(x-y) 3)(a+b)^2-2a(b+1)-a^2b÷ab=a^2+2a...
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