计算(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)-3^64/2要详细过程急!_数学解答

计算(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)-3^64/2
要详细过程
急!

人气：438 ℃　时间：2020-02-05 16:34:26

解答

原式=（3-1）(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)-3^64/2
=(3^2-1))(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)/2-3^64/2
=（3^32-1)(3^32+1)/2-3^64/2
=3^64/2-1/2-3^64/2
=-1/2