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化简2^4n+1-[(4^2n-1)+16^n]吗?如果不能,说明理由
人气:308 ℃ 时间:2020-09-14 12:59:24
解答
2^4n+1-[(4^2n-1)+16^n]
=2^4n+1-[(2^2)^2n-1)+(2^4)^n]
=2^4n+1-[2^4n-2+2^4n]
=2^4n+1-2^4n-2-2^4n]
=2^3*2^4n-2-2^4n-2-2^2*2^4n-2
=2^4n-2(2^3-1-2^2)
=2^4n-2(8-1-4)
=3*2^4n-2
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