∫x²/（2x+1)dx
=1/2∫2x²/（2x+1)dx
=1/2∫（2x²+x-x）/（2x+1)dx
=1/2∫[x-x/（2x+1)]dx
=1/2∫[x-1/2+1/2（2x+1)]dx
=1/2*[（1/2x²--1/2x+1/4ln（4x+2)]+C
=1/4x²-1/4x+1/8ln（4x+2)+C
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