> 数学 >
因式分解:
(1)
(x+1)(x+3)(x+5)(x+7)+15
(2)
6x²-6y²+5xy-4x+7y-2
人气:274 ℃ 时间:2020-04-16 05:22:18
解答
1.(x+1)(x+3)(x+5)(x+7)+15
=[(x+1)(x+7)][(x+3)(x+5)]+15
=(x^2+8x+7)(x^2+8x+15)+15
=(x^2+8x+7)[(x^2+8x+7)+8]+15
=(x^2+8x+7)^2+8(x^2+8x+7)+15
=[(x^2+8x+7)+3][(x^2+8x+7)+5]
=(x^2+8x+10)(x^2+8x+12)
=(x^2+8x+10)(x+2)(x+6)
2.6x²-6y²+5xy-4x+7y-2
=(3X-2Y)(2X+3Y)-(4X-7Y)-2
=(3X-2Y+1)(2X+3Y-2)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版