Y=1/8x+1/2
BP=4/3
因为三角形ABC等边所以角A=角b=60°所以角AFQ=BPE=FEC=30°
所以Y=二分之一AF
AF=AC-1/2EC
=AC-1/2(ab-be)
=ac-1/2(ab-1/2x)
=ac-1/2ab+1/4x
=2-1+1/4x
=1/4x+1
所以1/2af=1/4x除以2+1除以2
=1/8x+1/2
所以y=1/8x+1/2
第二问就是把第一问的结论代入
PQ重合则aq+pb+2因为AQ=Y PB=X
所以代入得：x+1/8x+1/2=2
9/8x=3/2
x=4/3