化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc(π-α)]
人气:385 ℃ 时间:2020-02-03 03:04:23
解答
[Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc(π-α)]= [(-sinα)\tanα] ×[(-cotα)\(-cosα)]×[secα\cscα]= [(-sinα)×cosα\sinα] ×[(cosα\sinα)\cosα)]×(sinα\cosα)=-c...
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