(tanα+β)/2=根号6/2 还是tan(α+β/2）=根号6/2 令（α+β/2）=x ,(α-β/2）=y ,则tanx=根号6/2 tanα=tan(x+y)=(tanx+tany)/(1-tanxtany) tanβ=tan(x-y)=(tanx-tany)/(1+tanxtany) 所以:tanαtanβ=((tanx+tany...