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解方程5/(x²-1)-4/(x²+2x-3)=2/(x²+4x+3)
人气:416 ℃ 时间:2020-03-27 05:03:43
解答
5/(x²-1)-4/(x²+2x-3)=2/(x²+4x+3)
5/(x+1)(x-1)-4/(x-1)(x+3)=2/(x+1)(x+3)
两边乘以(x+1)(x-1)(x+3),得
5(x+3)-4(x+1)=2(x-1)
5x+15-4x-4=2x-2
x+11=2x-2
-x=-13
x=13
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