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用指向函数的指针作函数参数,求分段函数当x<0时,y=x+2;当0≤x<5时,y=3x-1;当x≥5时,y=x(x-1)
人气:190 ℃ 时间:2020-04-12 16:04:57
解答
double fun1(double x){return x+2;}double fun2(double x){return 3*x-1;}double fun3(double x){return x*(x-1);}void main(){double x;scanf("%lf",&x);double (*fun)(double);//函数指针if(x
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