已知x-y=1 求代数式x^4-xy^3-x^3y-3x^2y+3xy^2+y^4的值
人气:186 ℃ 时间:2019-08-17 21:52:57
解答
x^4-xy^3-x^3y-3x^2y+3xy^2+y^4=(x^4-x^3y)-(xy^3-y^4)-(3x^2y-3xy^2)=x^3(x-y)-y^3(x-y)-3xy(x-y)而x-y=1=x^3-y^3-3xy=(x-y)(x^2+xy+y^2)-3xy=x^2+xy+y^2-3xy=x^2-2xy+y^2=(x-y)^2=1
推荐
- 当x=2,y=1时,代数式x^4-xy^3-x^3y-3x^2y+3xy^2+y^4
- 已知x+y=2,xy=-8,求代数式3x^2y+3xy^2-18xy的值
- 已知x^4+y^4=50,x^2y-xy^2=14,求代数式x^4-y^4+3xy^2-5x^2y+3x^2y+2y^4的值
- 若xy=-2,x+y=3,求代数式(3xy+10y)+5x- (2xy+2y-3x)的值
- 已知xy/x+y=2,求代数式3x−5xy+3y−x+3xy−y的值.
- Do you like s____?We have many c____.For example:v____ club,b______ club,p____ club,t___ club
- 已知向量a(sinx,cosx)向量b(sinx,1)f(x)=a·b求当x∈[-π/3,4π/3)时f(x)值域
- 数学的算数平方根
猜你喜欢