[﹙x/2+3y﹚²﹣﹙y/2﹢x﹚²+﹙3x-y/2﹚²-﹙x／2+3y﹚﹙3y-x2)]÷x/2
(中括号内,第一、四项提取(X/2+3Y),第二、三项用平方差公式)
=［(X/2+3Y)(X/2+3Y-3Y+X/2)+(3X-Y/2+Y/2+X)(3X-Y/2-Y/2-X)］*2/X
=［X^2/2+3XY+8X^2-4XY］*2/X
=［17/2X^2-XY］*2/X
=17X-2Y.