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数学
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化简:sin^6α+cos^6α+3sin^2α*cos^2α=?
人气:204 ℃ 时间:2019-12-24 09:47:19
解答
sin^6α+cos^6α+3sin^2α*cos^2α
=(sin^2α+cos^2α)(sin^4α-sin^2α*cos^2α+cos^4α)+3sin^2α*cos^2α
=sin^4α+2sin^2α*cos^2α+cos^4α
=(sin^2α+cos^2α)^2
=1
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