(y+2)÷4-(2y-3)÷6=1
（y+2）/4-(2y-3)/6＝1
(6y+8)/24-(8y-12)/24=1
(6y+8-8y+12)/24=1
6y-8y+20=24
-2y=4
y=-2y不是等于0吗不好意思，算错了，好多年没动笔了y到底得多少啊拜托准确率高一点多谢(3y+6-4y+6)/12=112-y=12y=0