(x^2+2)^2-3x^2-6,分组分解法,分解因式 x^3-x^2y-xy^2+y^3,分组分解法,分解因式
人气：247 ℃ 时间：2020-06-14 15:51:28
解答
(x^2+2)^2-3x^2-6=(x^2+2)^2-3(x^2+2)=((x^2+2)-3)(x^2+2)=(x^2-1)(x^2+2)=(x+1)(x-1)(x^2+2)x^3-x^2y-xy^2+y^3=(x^3-x^2y)-(xy^2-y^3)=x^2(x-y)-y^2(x-y)=(x^2-y^2)(x-y)=(x+y)(x-y)(x-y)=(x+y)(x-y)^2
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