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求极限:limx趋向于0 (e)^(x)^2-1/ln(1+3x^2)
人气:182 ℃ 时间:2020-01-30 01:14:40
解答
limx趋向于0 [e^(x^2)-1]/ln(1+3x^2)]用洛必达法则:[e^(x^2)-1/ln(1+3x^2)]'=2xe^(x^2)[ln(1+3x^2)]'=6x/(1+3x^2)[2xe^(x^2)]/[6x/(1+3x^2)=(1/3+x^2)e^(x^2)limx趋向于0 [e^(x^2)-1]/ln(1+3x^2)]=limx趋向于0 (1/3...
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