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求(sinx-cosx)/(sinx+cosx)^(1/3)的不定积分
人气:268 ℃ 时间:2020-04-08 03:10:15
解答
∫(sinx-cosx)/(sinx+cosx)^(1/3)dxlety= sinx + cosxdy = (cosx - sinx) dx∫(sinx-cosx)/(sinx+cosx)^(1/3)dx= -∫dy/y^(1/3)=-(3/2)y^(2/3) + C=-(3/2)(sinx + cosx)^(2/3) + C
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