> 数学 >
(-xy^2z^3)^2×(-x^2y)^3÷(2x^2yz^2)怎么计算
人气:251 ℃ 时间:2019-12-05 02:46:10
解答
(-xy^2z^3)^2×(-x^2y)^3÷(2x^2yz^2)
=(x^2y^4z^6)×(-x^6y^3)÷(2x^2yz^2)
=-1/2*x^(2+6-2)y^(4+3-1)z^(6-2)
=-x^6y^6z^4/2
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版