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数学
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a-8b=8 5a+4b=51
求解这个方程组
人气:156 ℃ 时间:2020-09-21 01:33:25
解答
a-8b=8 ①
5a+4b=51②
由①得:a=8+8b代入②
5(8+8b)+4b=51
40+40b+4b=51
44b=11
b=1/4
∴a=8+8×1/4=10
即:方程组的解为a=10;b=1/4
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