如果一个正数的两个平方根a+1和3a-5,求a值.
人气：255 ℃ 时间：2020-05-18 22:35:45
解答
可知a+1=-（3a-5）解得a=1要过程因为正数的两个平方根互为相反数，所以a+1=-（3a-5），即a+1=5-3a，解得a=1
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