y=sin(2x+π/2)+2sinαcosα+1最小正周期是?_数学解答

y=sin(2x+π/2)+2sinαcosα+1最小正周期是?

人气：454 ℃　时间：2020-02-05 23:49:33

解答

y=sin(2x+π/2)+2sinxcosx+1
=cos2x+sin2x+1
=√2(√2/2cos2x+√2/2sin2x)+1
=√2sin(2x+π/4)+1
最小正周期T=2π/2=π