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数学
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求y=7-2x+1/3(3+2x-x²)^(1/2)的最大值
人气：398 ℃ 时间：2020-07-14 05:02:17
解答
y=7-2x+1/3(3+2x-x²)^(1/2)=5-2(x-1)+1/3[4-(x-1)²]^(1/2)
令 2cosA=x-1 0
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