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计算:(1+2²)(1+2∧4)……(1+2∧12)
人气:299 ℃ 时间:2020-06-18 11:29:39
解答
(1+2²)(1+2∧4)……(1+2∧12)
=(1-2²)(1+2²)(1+2∧4)……(1+2∧12)/(-3)
=(1-2^4)(1+2^4)...(1+2^12)/(-3)
=...
=(1-2^24)/(-3)
=(2^24-1)/3
=5592405
此题如仍有疑问,欢迎追问!2012²-4024×2011+2011²
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