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己知cos(兀/4一a)=3/5,sin(5兀/4十b)=-12/13,a属于(兀/4,3兀/4),b属于(O,兀/4).求sin(a+...
己知cos(兀/4一a)=3/5,sin(5兀/4十b)=-12/13,a属于(兀/4,3兀/4),b属于(O,兀/4).求sin(a+b)的值
人气:146 ℃ 时间:2020-05-16 05:20:39
解答
cos(π/4一a) = cos(a-π/4) = 3/5 ==> sin(a-π/4) = 4/5 sin(5π/4+b) = -sin(π/4+b) ==> sin(b+π/4) = 12/13;cos(b+π/4) =5/13 sin(a+b)=sin[(a-π/4)+(b+π/4)] = 56/65 /*两角和公式
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