(-3×a3×b²)²×(-2/3×a×b×c)×3/4×a×c²
=(-3)×(-2/3)×3/4×a^(6+1+1)×b^(4+1)×c^(1+2)
=3/2a^8×b^5×c^3(-3×a的3次方×b)²×(-3分之2×a×b×c)×4分之3×a×c²原题是这样的，请在回答一遍！感谢！(-3×a的3次方×b)²×(-3分之2×a×b×c)×4分之3×a×c²=(-3)×(-2/3)×3/4×a^(3×2+1+1)×b^(2+1)×c^(1+2)=3/2a^8×b^3×c^3