1/(3-x) - 2 = 1/(x-3) + (4-2x)/(3x^2-27)移项：1/(3-x) - 2 - 1/(x-3) - (4-2x)/(3x^2-27) = 0- 1/(x-3) - 2 - 1/(x-3) - 2 (2-x)/{3（x+3)(x-3)} = 02/(x-3) + 2 + 2(2-x)/{3（x+3)(x-3)} = 01/(x-3) + 1 + (2-x)...