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解方程组{x²-2xy-8y²=0 {(x+y)²-3(x+y)-10=0
人气:436 ℃ 时间:2020-05-31 10:36:09
解答
x²-2xy-8y²=0可以变形为(x-4y)(x+2y)=0,解得x-4y=0或x+2y=0(x+y)²-3(x+y)-10=0可变形为((x+y)-5)((x+y)+2)=0得x+y=5或x+y=-2因此可配成四个方程组,解以此为x=4,y=4或x=-1.6,y=-0.4或x=...
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