求解下列方程组,当有无穷多解时求其通解 a+b+2c-d=0 2a+b+c-d=0 2a+2b+c-2d=0 亲,求详解,
人气:170 ℃ 时间:2020-03-29 13:15:27
解答
a+b+2c-d=0----(1),2a+b+c-d=0----(2),2a+2b+c-2d=0----(3),(1)×2-(2):b+3c-d=0----(4),(2)-(3):-b+d=0,b=d----(5),把(5)代入(4):C=0,把(5),C=0代入(1):a=0,∴b=d,a=c=0.
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