分解因式:(x的平方-6xy+9y的平方)-1
人气：105 ℃ 时间：2020-01-30 04:25:08
解答
原式=(x²-6xy+9y²+1)(x²-6xy+9y²-1)
=(x²-6xy+9y²+1)[(x-3y)²-1]
=(x²-6xy+9y²+1)(x+3y+1)(x+3y-1)
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